For a complete lesson on motion word problems, go to http://www.yourteacher.com – 1000+ online math lessons featuring a personal math teacher inside every lesson! In this lesson, students learn to solve introductory “motion” word problems — for example, cars traveling in opposite directions, bikers traveling toward each other, or one plane overtaking another. Students should first draw a diagram to represent the relationship between the distances involved in the problem, then set up a chart based on the formula rate times time = distance. The chart is then used to set up the equation.
thx i have an exame in 2 days it helps
Helpful, but slow!
@Someoneyoudontknow13 i know right?
thanks
i have to study for a test thats on tuesday.
DARN YOU MATH!!
thanks a ton that helps alot with my math homework
Thank you sooo much! I’m in college and this is on our final today! I’ve always sucked at math and your videos are sooooooooooooooooo useful!
Good teacher, but very stale.
thanks, i have a test on this tomorrow
you have
no life
this actually helped a lot i hate algebra class though =P
i suck at these but this helped a lot. thanks
Too easy
@esthermiso Exactly. He gave up explaining the process and jumped to the answer.
@esthermiso he solved the equation if you want to learn that look for multi step equations
he’s not sweating in front of class doing math probs lol
@esthermiso ok, so his equation was 55x + 75x = 520.
first you add the 55x and 75x which gives you 130.
soo, 130x = 520
divide 520 and 130 which equals 4.
so. x = 4. or {4}
@thereally28 the two distances added together equal 520. problem is you dont know the distance of the two cars. so he said the formula to get the distance is rate x the time. he made time x. the rate for the two cars were 55 mph and 75 mph. so 55x + 75x = 520. so solve for x. 55x plus 75 x equals 130. 520 divided by 130 is 4. if you dont get it dont feel ashamed. my parents think im stupid. but the thing is word problems are hard for me. especially mixture problems
i.e. Say distance is 100. Rate is 5 and 10. The time will be 20 for the first and 10 for the second. Clearly 20 is not equal to 10. So your assumption is incorrect. They could still leave at the same time on the clock say 9 am, but the time taken to cover the distance will be different. Please explain your assumption
How did you assume that the two times are equal?. The time used in the equation R x T = D refers to the “amount” of time taken to cover distance D at a speed of R. You assumed that since they leave at the same time (i.e. say they leave at 9 am) the amount of time is same? That doesnt make sense at all
How did he suddenly get 4??
@AwSoMeSaUcEeEe thanks a million…… i was about to get upset!!!!!!
@AwSoMeSaUcEeEe thanks a million…… i was about to get upset!!!!!!
@joeydifranco0422 his son
thumps up if your are here for the California STAR test tomorrow